Question

2 ?? Find the angle between each of the following pairs of vectors: (a) \vec{A} = -2.00\hat{i} + 6.00\hat{j} and \vec{B} = 2.00\hat{i} - 3.00\hat{j} (b) \vec{A} = 3.00\hat{i} + 5.00\hat{j} and \vec{B} = 10.00\hat{i} + 6.00\hat{j} Figure E1.28 y \vec{B} (15.0 m) \vec{D} (10.0 m) 30.0° 53.0° x 25.0° O \vec{C} (12.0 m) \vec{A} (8.00 m)

          2
?? Find the angle between each of the following pairs of
vectors:
(a) \vec{A} = -2.00\hat{i} + 6.00\hat{j} and \vec{B} = 2.00\hat{i} - 3.00\hat{j}
(b) \vec{A} = 3.00\hat{i} + 5.00\hat{j} and \vec{B} = 10.00\hat{i} + 6.00\hat{j}
Figure E1.28
y
\vec{B} (15.0 m)
\vec{D} (10.0 m)
30.0°
53.0°
x
25.0°
O
\vec{C} (12.0 m)
\vec{A} (8.00 m)

2
?? Find the angle between each of the following pairs of
vectors:
(a) A⃗ = -2.00î + 6.00ĵ and B⃗ = 2.00î - 3.00ĵ
(b) A⃗ = 3.00î + 5.00ĵ and B⃗ = 10.00î + 6.00ĵ
Figure E1.28
y
B⃗ (15.0 m)
D⃗ (10.0 m)
30.0°
53.0°
x
25.0°
O
C⃗ (12.0 m)
A⃗ (8.00 m)

Added by Roger J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sikandar Baig

Step 1

First, let's find the magnitude of vector A using the formula: magnitude = sqrt(Ax^2 + Ay^2) For vector A = -2.00i + 6.00j, we have Ax = -2.00 and Ay = 6.00. So, magnitude of A = sqrt((-2.00)^2 + (6.00)^2) = sqrt(4 + 36) = sqrt(40) = 6.32m Show more…

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Thanks for your feedback!

Vectors: A = -2.00i + 6.00j and B = 2.00i - 3.00j A = 3.00i + 5.00j and B = 10.00i + 6.00j Figure E1.28 B = 15.0m D = 10.0m 30.0Â° 53.0Â° 25.0Â° C = 12.0m A = 8.00m