we can model the crankcase of on automobile as q flat place of l0cm thickness60cm length and a 2

Name: we can model the crankcase of on automobile as q flat place of l0cm thickness60cm length and a 20cm width consider the surface temperature of the crankiness is 77c when the vehicle moves wit 35698
Uploaded: 2023-06-17T04:14:42-08:00
Duration: 4 min 59 s
Channel: Sri K
Description: we can model the crankcase of on automobile as q flat place of l0cm thickness60cm length and a 20cm width consider the surface temperature of the crankiness is 77c when the vehicle moves wit 35698

We can model the crankcase of on automobile as q flat place...

We can model the crankcase of an automobile as a flat plate of 10 cm thickness, 60 cm length, and a 20 cm width. Consider the surface temperature of the crankcase is 77Â°C when the vehicle moves with a speed of 108 km/hr. Moreover, the vibrations of the engine and chassis cause the boundary layer on the crankcase to transition into a turbulent one very close to the leading edge. As a thermal engineer, you need to determine the rate of heat transfer from the crankcase to the ambient air.

Transcript

00:01 In this question we are given here crankcase so the crankcase of an automobile crankcase of the automobile the approximately the length we are given here of the crankcase that l which is equal to 0 .6 meter width that b which is equal to 0 .2 meter and the deep that is the depth we are given here it is 0 .1 meter deep.

00:27 Now assume the surface temperature of the crank the surface temperature t s which is equal to we can write 350 kelvin.

00:36 Now in this case the atmospheric pressure at 276 and the heat flow we need to estimate the heat flow here that is q c here we need to find the heat loss from the crankcase this is a heat loss we need to find heat loss from the crankcase heat loss from the crankcase so here we can write let's solve this question and find the answer first let's find out the re number so here we can write the reynolds number we need to be find so the re which is equal to we can write 0 multiplied by u infinity and l divided by we can write values mu which is equal to we can write 1 .092 multiplied by we can write 30 multiplied by we can write 0 .6 divided by we can write 19 .123 multiplied by we can write 10 -6.

01:44 Now the re number which is equal to answer is 1 .03 multiplied by we can write 10 -6.

01:51 Here let's find out the average nus here of the nusselt number so here we want to find average nusselt number so the average nusselt number that is nul here nul average which is equal to we can write hc average multiplied by l divided by we can write k now which is equal we can write 0 .036 multiplied by we can write the pr raised to 1 divided by 3 and re raised to 0 .8 and l now we here we will using this we know the pr value and the re we will substitute a value in this formula so nul which is equal to 0 .036 multiplied by we can write 0 .71 raised to 1 divided by 3 multiplied by we can write 1 .03 multiplied by we can write 10 -6.

02:55 Here we can write raised to 0 .8 raised to 0 .8.

02:58 Now the nul average which is equal to answer is 2075...

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