Question

15\Omega 12V 2.0F when the switch is closed, how many seconds go by before 63% of the maximum charge accumulates on the capacitor? 180 s 360 s 24 s 30 s

          15\Omega
12V
2.0F
when the switch is closed,
how many seconds go by
before 63% of the
maximum charge accumulates
on the capacitor?
180 s
360 s
24 s
30 s

15Ω12V
2.0F
when the switch is closed,
how many seconds go by
before 63% of the
maximum charge accumulates
on the capacitor?
180 s
360 s
24 s
30 s

Added by Donald W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shaiju T

Step 1

The formula for the maximum charge on a capacitor is Q = CV, where Q is the charge, C is the capacitance, and V is the voltage. Given that the capacitance is 2.0 F and the voltage is 2 V, we can calculate the maximum charge as follows: Q = (2.0 F)(2 V) = 4.0 C Show more…

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When the switch is closed, how many seconds go by before 63% of the maximum charge accumulates on the capacitor? 15 W 2 V 2.0 F When the switch is closed, how many seconds go by before 63% of the maximum charge accumulates on the capacitor? 0180 s 0360 s 024 s 030 s