Question

Which of the following is a linear equation in $x$, $y$ and $z$? None of the given option $x^2 + y + 8z = 5$. $x^3 - 5y - az = 11$, where $a \in \mathbb{R}$ $x^2 + y + 8z = 5$. None of the given option $\cos x - y + z = 0$. $\pi - \sqrt{x^2} + y - z - 1 = 0$

          Which of the following is a linear equation in $x$, $y$ and $z$?
None of the given option
$x^2 + y + 8z = 5$.
$x^3 - 5y - az = 11$, where $a \in \mathbb{R}$
$x^2 + y + 8z = 5$.
None of the given option
$\cos x - y + z = 0$.
$\pi - \sqrt{x^2} + y - z - 1 = 0$
        
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Which of the following is a linear equation in x, y and z?
None of the given option
x^2 + y + 8z = 5.
x^3 - 5y - az = 11, where a āˆˆā„
x^2 + y + 8z = 5.
None of the given option
cos x - y + z = 0.
Ļ€ - √(x^2) + y - z - 1 = 0

Added by Magdalena B.

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Which of the following is a linear equation in y and z? None of the given options g = 28 + h + 2z 5y - az = 11, where a ∈ R x^2 + y + 8z = 5 None of the given options cosĆŽĀø = 0 y - z + 1 = 0
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Transcript

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00:01 We need to know how many solutions this system is going to have.
00:03 So to do that, we're just going to go ahead and start solving and see what happens.
00:07 So i'm going to have over here, work with my x's, and i'm going to eliminate those.
00:11 To do that, let me number my equations.
00:17 I'm going to take this first equation and multiply it by negative 2, and then i'm going to add that 2 equation 2.
00:24 So i'm going to multiply that, so it's going to be negative 2x minus 4y, minus 6 z, equals 0.
00:30 Then i'll combine that with equation 2 to get negative y minus 5 z equals to 0.
00:40 Now i'm going to do the same thing, but this time i'm going to multiply it by negative 4...
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