00:01
Here we are given with two samples.
00:03
We will consider the samples one by one.
00:05
Sample size n is 9 and x bar equal to summation xi by n which is 7 .5 plus 6 .7 plus etc.
00:15
Plus 6 .4 divided by 9.
00:18
So it is 60 .2 divided by 9.
00:21
So final answer is 6 .6889.
00:24
Hence sample sign 6 bar equal to 6 .6889.
00:29
And the standard deviation.
00:30
Is square root of summation i is equal to 1 to n xa minus xx4 the whole square by n minus 1 so which is square root of 7 .5 minus 6 .6 .889 the whole square plus etc plus 6 .4 minus 6 .89 the square divided by 8 which is equal to square root of 5 .7289 divided by 8.
01:01
So it is equal to square square root of 0 .7161 and the final answer is 0 .8462.
01:08
Therefore s1 is 0 .8462 that is the standard deviation of second sample.
01:14
Now consider the sample 2.
01:16
So here we are considering the sample size.
01:20
That is only 7 samples we are considering...