Question

Write the equation of the ellipse $4x^2 + 16y^2 - 32x + 96y + 144 = 0$ in standard form $\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1$, where: h = 4 k = -3 a = 4 b = 2

          Write the equation of the ellipse $4x^2 + 16y^2 - 32x + 96y + 144 = 0$ in standard form
$\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1$,
where:
h = 4
k = -3
a = 4
b = 2

Write the equation of the ellipse 4x^2 + 16y^2 - 32x + 96y + 144 = 0 in standard form
((x - h)^2)/(a^2) + ((y - k)^2)/(b^2) = 1,
where:
h = 4
k = -3
a = 4
b = 2

Added by Jermaine N.

Precalculus with Limits

Ron Larson 2nd Edition

Thanks for your feedback!

Write the equation of the ellipse 4x^(2)+16y^(2)-32x+96y+144=0 in standard form where: ((x-h)^(2))/(a^(2))+((y-k)^(2))/(b^(2))=1 h= k= a= b= Write the equation of the ellipse 4x2+ 16y2 - 32x + 96y+144 = 0 in standard form x-hy-k =1 22 62 where: h = 4 k= -3 a= 4 b=