00:01
For this question, the part of the anova table is already filled and it is as follows.
00:08
Source, in this one we have treatment, blocks and error and then sum of squares, then degrees of freedom and then mean squared.
00:23
So based on the given data, we will fill out the missing data here, 177 .7667, 252 .7667 and then degrees of freedom is 4 here and here it is 24467 .2 and 2022 .133.
00:49
So we can infer the sum of squares for the blocks with the degrees of freedom and mx.
00:59
So for blocks, sum of squares equals to 4 times 177 .766.
01:08
667 and it comes out to be 711 .0667.
01:18
Similarly, for the degrees of freedom for error can be calculated by, degrees of freedom for error can be calculated by dividing sum of squares by mx.
01:31
So that gives 2022 .133 divided by 252 .767 and it comes out to be 8.
01:49
So this one is 8.
01:52
And the degrees of freedom of treatment is number of columns minus 1, which is, there are, sorry number of rows minus 1.
02:00
Here we have 3 rows belonging to 3 blocks.
02:02
So degrees of freedom of treatment is number of rows minus 1...