00:01
For this question, we're told that we have a vector b of magnitude 6 .4 centimeters in a direction, which is 63 degrees below the positive x -axis.
00:11
So then the angle theta -b is going to be 0 minus 63 degrees as defined by the angle from the positive x -axis.
00:18
So theta -b is negative 63 degrees.
00:20
And vector c has the same magnitude as vector b, and we're told that the angle theta -c is 22 degrees above the positive x -axis, so theta -c is just 22 degrees.
00:29
And we're told that vector c is equal to vector a plus vector b.
00:42
And so we are asked to draw the vector addition diagram for these vectors roughly to scale then.
00:50
Okay.
00:51
So in order to do that, we'll just draw our x, y, axis here real quick.
00:57
Okay.
00:59
And we're told that we have a vector, i'll draw it in red, vector b, which is 62 or 63 degrees below.
01:06
So it's going to be something like this.
01:08
So this is vector b.
01:13
This is at an angle.
01:15
I'll draw the angles in green.
01:17
This angle here is theta b.
01:21
Okay.
01:22
And then we also have the resultant vector, vector c, something like this.
01:32
But it's at an angle, which we call theta c, 22 degrees above.
01:39
And then how would we get from b to c? well, we'd have the vector a.
01:44
I'll draw vector a in blue.
01:46
That would go from b to c.
01:48
That we would need to add to it.
01:50
Vector a.
01:52
So relative to the x axis, vector a would look something like this, right? i just moved vector a over there to go from a plus b to equal to c.
02:05
And then the angle, i'll put it in blue, that would be the angle theta a that makes with the x axis.
02:13
So we want to find a in theta a.
02:16
Okay.
02:17
So there's our diagram, and that was part a...