you're kneeling 1 m above the ground and you're shooting an arrow at 30 30\deg above the horizontal so you're a metre up and then 30\deg and then it tells you that you are 97 m away from a tree and that the arrow stays in the air for 2.4 seven seconds if I'm not mistaken and then it asked you basically was the initial velocity
Added by Valerie M.
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You shoot an arrow into the air. Two seconds later $(2.00$ s) the arrow has gone straight upward to a height of 30.0 $\mathrm{m}$ above its launch point. (a) What was the arrow's initial speed? (b) How much time did it take for the arrow to first reach a height of 15.0 $\mathrm{m}$ above its launch point?
Supratim P.
An archer shoots an arrow at a 75.0 m distant target; the bull's-eye of the target is at same height as the release height of the arrow. (a) At what angle must the arrow be released to hit the bull's-eye if its initial speed is 35.0 m/s? In this part of the problem, explicitly show how you follow the steps involved in solving projectile motion problems. (b) There is a large tree halfway between the archer and the target with an overhanging horizontal branch 3.50 m above the release height of the arrow. Will the arrow go over or under the branch?
An archer shoots an arrow at a 74.0 m distant target, the bull's-eye of which is at the same height as the release height of the arrow. (a) At what angle must the arrow be released to hit the bull's-eye if its initial speed is 36.0 m/s? (Although neglected here, the atmosphere provides significant lift to real arrows.) ° (b) There is a large tree halfway between the archer and the target with an overhanging branch 3.50 m above the release height of the arrow. Will the arrow go over or under the branch? under/over
Shaiju T.
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