00:01
So here the solution for this problem is, as from the given information, we have a square.
00:07
First, we have a square.
00:09
And in the second, we have a circle.
00:12
And third, we have quarter.
00:16
So by using this, if we draw a diagram, we will see the diagram like this.
00:22
So here, the area which will be a1 will be calculated as the side multiplied with side.
00:30
Which will give us the a 1 as equals to a plus b whole square a plus b whole square which will be 178 .2 plus 271 .4 whole square multiplied with millimeter square so this will be equals to 2 .2 .2 .140 .16 mm .m.
01:03
And now for x1 bar it will be a plus b divided by 2, which will be 224 .8 millimeters.
01:16
So here we got the x1 bar as 224 .8 millimeters.
01:22
And for a2, which is area 2, it will be equals to area of circle.
01:31
Area of circle.
01:33
We know that the area of circle is pi multiplied with c square, which will be 3 .14, multiplied with 125 .1mm whole square...