Q7 VL(t) 10 -1 0 1 3 iL(t) + VL(1) 3 H For the circuit shown above, the voltage v?(t) across the 3 H inductor is as shown, then the inductor current at t =1 seconds, iL(1) is
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From the graph vL(t) is linear from vL(−1)=+10 V to vL(1)=−10 V, so for −1 ≤ t ≤ 1 vL(t) = −10 t. (For completeness, for 1 ≤ t ≤ 3 the line is vL(t)=5t−15, and vL(t)=0 for t<−1.) Show more…
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