00:01
Hi, in this question we have given data for t1, t2, t3 and t4.
00:05
T means trial.
00:06
We have given potassium phthalate mass, volume of naoh, final in milliliter, volume of naoh, initial in milliliter.
00:12
We need to find out volume of naoh that would be final volume minus initial volume that will be 17 .01, 42, 16 .31, 43, 16 .01, 44, 18 .50.
00:34
Number of moles of naoh will be same with number of moles of potassium phthalate because potassium phthalate, k, h, c8, h4, oh is 2, naoh mole ratio is 1 is to 1.
00:51
So calculation of number of moles of k, h, c8, h4, oh will give number of moles of naoh, number of moles of potassium phthalate will be equal with mass by molecular weight of potassium phthalate that is 204 .22.
01:10
This is gram, this is gram per mole.
01:11
Ultimately we will have number of moles in mole.
01:15
As we have given mass for different trial, we will put this mass value here.
01:22
We will get number of moles of naoh and this as same.
01:27
This will be 2 .07 into 10 to the power minus 3, this is same 2 .07 into 10 to the power minus 3.
01:35
Next, 1 .98 into 10 to the power minus 3, 1 .98 into 10 to the power minus 3.
01:42
Trial 3, 2 .07 into 10 to the power minus 3, 2 .07 into 10 to the power minus 3...