00:02
Hi, here in this given problem there is a series l -c -r circuit.
00:14
In this circuit, the voltage amplitude that is given to us, voltage amplitude means peak voltage, that is 240 volt, value of resistance, that is 150 oom, and that is 150 oom, and and capacity reactance that is also given to us and this is 600 oom but inductive reactance that is missing this is not given to us as this is a series circuit so the current passing through it will remain same current passing through all these three circuit elements will be same it is given that the voltage amplitude across the capacitor that is 720 volt so in the first part of the problem we have to find current amplitude and we will find current amplitude for the capacitor that will remain same for whole of this circuit so that will be given by i -o is equal to voltage amplitude across capacitor using homes law i equals to v by r and divided by xc means here this is 720 volt divided by 600 om so current amplitude for this circuit comes out to be equal to 1 .2 ampere which is the answer for the first part of this problem now in the second part of the problem we have to find impedance of the circuit.
02:29
So using oms law again, impedance will be given by the total impedance, total opposition of the circuit.
02:37
Voltage amplitude for whole of the circuit divided by current amplitude for whole of the circuit.
02:43
Means this is 240 divided by 1 .2.
02:46
So here it will come out to be equal to 200 oom.
02:52
Which becomes the answer for the second part of this problem.
02:59
Now in the third part of the problem we have to find two possible values of inductive reactants.
03:07
So here two possible values of the inductive reactants will be based upon the fact that either xl may be greater than xc or xl may be less than xc.
03:20
Whatever may be the case, impedance is given as z square is equal to xl minus xc square plus r square means this is square of 200 is equal to xl that is missing xc which is 600 square plus r which is 150 to the whole square...