00:01
In this question, there is a steel pipe.
00:05
This is the steel pipe.
00:09
The water is flowing.
00:13
Water is flowing in the steel pipe at 20 degrees celsius.
00:18
The density of the water is 1 ,000 kg per meter cube.
00:24
The viscosity, dynamic viscosity is given 0 .001 pascal seconds.
00:34
Is the length of the steel pipe and diameter of the steel pipe is given as 2 .5 centimeter the mass flow rate is given 0 .0 4 kg per seconds we are calculating the pressure drop due to a friction in the pipe section so first of all we are finding the friction so in case of laminar flow this is 64 divided by renounce number so first of all we are checking the reynolds number to check the flow is laminar or turbulence.
01:12
So first of all, we are calculating the reynolds number that is equal to density speed diameter divided by viscosity.
01:20
In this question, speed is not given but mass flow rate is given.
01:24
So mass flow rate is equal to density times volume.
01:29
So this is area times speed.
01:32
So speed is equal to mass flow rate divided by density times area area is the cross -sectional area so we can write here pi d squared divided by four so we can write four in numerator so this is the uh this is the velocity so rinald number is equal to density speed is equal to mass fluid four divided by pi d square density this is diameter this is mu so density is now diameter is cancelled out so this is four times pass flow rate divided by pi mu diameter and density is cancelled out so this is 0 .04 pi this is 0 .001 dynamic viscosity and the diameter is 2 .5 centimeters so we can write 0 .025 so the renown number is equal to renal number is equal to 037 .18.
02:42
This renown number is less than 2 ,300.
02:45
So it meets the flow is leminar flow...