Water at \( 200^{\circ} \mathrm{F} \) is pumped from a storage tank at the rate of \( 50 \mathrm{gal} / \mathrm{min} \). The motor for the pump supplies work at the rate of 2 (hp). The water goes through a heat exchanger, giving up heat at the rate of \( 40.000 \mathrm{Btu} / \mathrm{min} \). and is delivered to a second storage tank at an elevation 50 ft above the first tank. What is the temperature of the water delivered to the second tank?
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First, we need to calculate the power input to the pump. Power is given by the formula: \[ \text{Power} = \text{Work done per unit time} = \text{Force} \times \text{Velocity} \] Given that the work done per unit time is 2 hp and the rate of pumping water is 50 Show more…
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