Question

Water is flowing from a horizontal pipe 48 feet above the ground. The falling stream of water has the shape of a parabola whose vertex (0,48) is at the end of the pipe (see figure). The stream of water strikes the ground at the point $(10 \sqrt{3}, 0) .$ Find the equation of the path taken by the water.

Name: Water is flowing from a horizontal pipe 48 feet above the ground. The falling stream of water has the shape of a parabola whose vertex (0,48) is at the end of the pipe (see figure). The stream of water strikes the ground at the point (10 √(3), 0) . Find the equation of the path taken by the water.
Uploaded: 2022-04-23T01:39:04-08:00
Duration: 2 min 13 s
Channel: Gregory Higby
Description: Water is flowing from a horizontal pipe 48 feet above the ground. The falling stream of water has the shape of a parabola whose vertex (0,48) is at the end of the pipe (see figure). The stream of water strikes the ground at the point (10 √(3), 0) . Find the equation of the path taken by the water.

          Water is flowing from a horizontal pipe 48 feet above the ground. The falling stream of water has the shape of a parabola whose vertex (0,48) is at the end of the pipe (see figure). The stream of water strikes the ground at the point $(10 \sqrt{3}, 0) .$ Find the equation of the path taken by the water.

Added by Charles E.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Gregory Higby

04/23/2022

Step 1

Since the vertex of the parabola is given as $(0, 48)$, we can use the vertex form of the equation of a parabola: \[ y = a(x - h)^2 + k \] where $(h, k)$ is the vertex of the parabola. Here, $h = 0$ and $k = 48$, so the equation simplifies to: \[ y = a x^2 Show more…

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Water is flowing from a horizontal pipe 48 feet above the ground. The falling stream of water has the shape of a parabola whose vertex (0,48) is at the end of the pipe (see figure). The stream of water strikes the ground at the point $(10 \sqrt{3}, 0) .$ Find the equation of the path taken by the water.