Question

Water is flowing in a straight horizontal pipe of variable cross section. Where the cross-sectional area of the pipe is 2.70·10^-2 m^2, the pressure is 10.50·10^5 Pa and the velocity is 0.610 m/s. In a constricted region where the area is 12.10·10^-4 m^2, what is the velocity? What is the pressure (in Pa)? (Assume an ideal fluid)

          Water is flowing in a straight horizontal pipe of variable cross section. Where the cross-sectional area of the pipe is 2.70·10^-2 m^2, the pressure is 10.50·10^5 Pa and the velocity is 0.610 m/s. In a constricted region where the area is 12.10·10^-4 m^2, what is the velocity?
What is the pressure (in Pa)? (Assume an ideal fluid)

Water is flowing in a straight horizontal pipe of variable cross section. Where the cross-sectional area of the pipe is 2.70·10^-2 m^2, the pressure is 10.50·10^5 Pa and the velocity is 0.610 m/s. In a constricted region where the area is 12.10·10^-4 m^2, what is the velocity?
What is the pressure (in Pa)? (Assume an ideal fluid)

Added by Colin F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

06/27/2022

Step 1

Given: a1 = 2.70 * 10^(-3) m^2 a2 = 12.10 * 10^(-4) m^2 v1 = 0.610 m/s Using the equation of continuity: a1v1 = a2v2 Substitute the values: 2.70 * 10^(-3) * 0.610 = 12.10 * 10^(-4) * v2 Solving for v2: v2 = (2.70 * 0.610) / 12.10 = 0.567 / 12.10 = 0.0469 m/s Show more…

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Water is flowing in a straight horizontal pipe of variable cross section. Where the cross-sectional area of the pipe is 2.70·10^-2 m^2, the pressure is 10.50·10^5 Pa and the velocity is 0.610 m/s. In a constricted region where the area is 12.10·10^-4 m^2, what is the velocity? What is the pressure (in Pa)? (Assume an ideal fluid)