00:01
In this question, it is given that the water treatment plan, which is commonly using the chlorination for destroying the bacteria, the byproduct chloroform, that is chcl3, a suspected carcinogen produced from hocl, formed by the reaction of cl2 and water, reacts with dissolved organic matter.
00:39
The united states, canada and the world health organization have settled a limit of 100 ppb of chcl3 in drinking water.
00:52
Converting this concentration into molarity, molality and mass percent, we have ppb is equal to mass of salute divided by mass.
01:21
Mass of solution into 10 rise to 9.
01:30
Chcl3 present in drinking water is equal to 100 ppb.
01:43
100 is equal to m by 1 into 10 rise to 9.
01:49
M is the mass of chl 3 present in 1 gram water, that is 1 into 10 rise to minus 7 grams.
02:03
Morality is m is equal to w by molecular weight into thousand by v in ml.
02:19
That is w is equal to 1 .10 rise to minus 7 grams.
02:29
1 .10 rise to minus 7 grams.
02:34
Molecular weight is equal to 119 .38 gram per mole.
02:43
Now v is the volume of solution, that is m by d is equal to 1 by 1 is equal to 1mm.
02:56
Morality is equal to 1 into 10 x to minus 7, divided by 119 .38 into 1 ,000 by 1 .1 ,000 by 1, which is equal to 8 .38 into 10x to minus 7 mol.
03:13
Now the molarity, molarity m is equal to w by molecular weight into thousand by w in grams...