Question

We are given two urns as follows: Urn A contains 5 red marbles, 3 white marbles and 8 blue marbles. Urn B contains 3 red marbles and 5 white marbles. A fair die is tossed; if 3 or 6 appears, a marble is chosen from B, otherwise a marble is chosen from A. Find the probability that, a. A red marble is chosen. b. A white marble is chosen. c. A blue marble is chosen.

Name: we are given two urns as follows urn a contains 5 red marbles 3 white marbles and 8 blue marbles urn b contains 3 red marbles and 5 white marbles a fair die is tossed if 3 or 6 appears a mar 63782
Uploaded: 2022-06-09T19:48:00-08:00
Duration: 1 min 49 s
Channel: Victor Salazar
Description: we are given two urns as follows urn a contains 5 red marbles 3 white marbles and 8 blue marbles urn b contains 3 red marbles and 5 white marbles a fair die is tossed if 3 or 6 appears a mar 63782

          We are given two urns as follows:
Urn A contains 5 red marbles, 3 white marbles and 8 blue
marbles.
Urn B contains 3 red marbles and 5 white marbles.
A fair die is tossed; if 3 or 6 appears, a marble is chosen from
B, otherwise a marble is chosen from A. Find the probability
that,
a. A red marble is chosen.
b. A white marble is chosen.
c. A blue marble is chosen.

Added by Pamela L.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Victor Salazar

06/09/2022

Step 1

- The die has 6 faces, and each face is equally likely to appear. - If a 3 or 6 appears, a marble is chosen from Urn B. The probability of this happening is: \[ P(\text{Urn B}) = \frac{2}{6} = \frac{1}{3} \] - If any other number (1, 2, 4, or 5) appears, a Show more…

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We are given two urns as follows: Urn A contains 5 red marbles, 3 white marbles and 8 blue marbles. Urn B contains 3 red marbles and 5 white marbles. A fair die is tossed; if 3 or 6 appears, a marble is chosen from B, otherwise a marble is chosen from A. Find the probability that, a. A red marble is chosen. b. A white marble is chosen. c. A blue marble is chosen.