We are standing on the top of a 112 feet tall building and launch a small object upward. The object's vertical position, measured in feet, after t seconds is h(t) = -16t^2 + 96t + 112. What is the highest point that the object reaches? feet
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The x-coordinate of the vertex is given by -b/2a, where a = 16 and b = 96. So, x = -96/(2*16) = -96/32 = -3. Therefore, the object reaches its highest point at t = 3 seconds. Show more…
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