We can use what we know about breaking vectors into their x- and y-components to expand this, as follows.
Before the collision
After the collision
$m_1 \vec{v}_{1x} + m_2 \vec{v}_{2ix} = m_1 \vec{v}_{1fx} + m_2 \vec{v}_{2fx}$
$m_1 \vec{v}_{1iy} + m_2 \vec{v}_{2iy} = m_1 \vec{v}_{1fy} + m_2 \vec{v}_{2fy}$
Applying this to the picture above, what is the y-component of the total momentum before the collision? (Enter your answer in kg $\cdot$ m/s).
156.99
Incorrect. Is there motion in the y direction before the collision? kg $\cdot$ m/s
What is the y-component of the total momentum after the collision? (Enter your answer in kg $\cdot$ m/s).
109.64
Incorrect. Apply the law of conservation of momentum. kg $\cdot$ m/s
If $m_1$ and $m_2$ are equal, what is true about the y-components of their velocities after the collision?
The velocities will have the same magnitude but opposite directions
The velocities will both be zero.
The velocities will be equal.