We have 1000 g of liquid Al that is at 973 K inside a non-heat transferring container. We add a little Cr2O3 at the same heat in order to convert Al completely to Al2O3. In order to have outputs from this exothermic reaction at a maximum of 1600 K, what is the extra Cr2O3 amount that should be added?
2Al + CrO = 2Cr + Al2O3
M = 27 g/mol
M = 52 g/mol
M = 16 g/mol
Al
Cr
CrO3(s)
Al2O3
19.37
114.8
9.31 x 10^-3
12.8 x 10^-3
31.76
21.76
8.98 x 10^3
-165700