Question

We have 200 mL of 25% SDS and need to make a 450 mL solution with a concentration of 0.5%. The molecular weight of SDS is 288.378. Therefore, mL of stock was added to mL of diluent.

Name: we have 200 ml 25 sds need to make 450 ml concentration of 05 solution the molecular weight of sds is 288378 therefore ml of stock was added to ml of dilutent 57515
Uploaded: 2022-03-20T08:44:34-08:00
Duration: 1 min 57 s
Channel: Raman S
Description: we have 200 ml 25 sds need to make 450 ml concentration of 05 solution the molecular weight of sds is 288378 therefore ml of stock was added to ml of dilutent 57515

          We have 200 mL of 25% SDS and need to make a 450 mL solution with a concentration of 0.5%. The molecular weight of SDS is 288.378. Therefore, ____ mL of stock was added to ____ mL of diluent.

Added by Douglas E.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Raman S

03/20/2022

Step 1

Given: - Volume of stock solution (V1) = 200 mL - Concentration of stock solution (C1) = 25% - Concentration of required solution (C2) = 0.5% - Volume of required solution (V2) = 450 mL Using the formula C1V1 = C2V2: 25% * 200 mL = 0.5% * V2 50 = 0.5 * V2 V2 = 50 Show more…

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We have 200 mL of 25% SDS and need to make a 450 mL solution with a concentration of 0.5%. The molecular weight of SDS is 288.378. Therefore, ____ mL of stock was added to ____ mL of diluent.