We know that 96.92% of Cecil students have Internet access at home. We take a sample of n = 18 students. Determine: P(At least one student does not have Internet at home) = ___________. Round your answer to four decimals.
Added by Miranda C.
Step 1
Since 96.92% of students have Internet access at home, the probability that a single student does not have Internet access is 1 - 0.9692 = 0.0308. Show more…
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