Question

We randomly selected ten (10) defendants in a state prison. They have been sentenced to prison (years) for: 3 4 7 7 11 12 12 19 22 23 Compute the margin of error at 95% confidence level of the years. (Round off to three decimal places if necessary).

Name: we randomly selected ten 10 defendants in a state prison they have been sentenced to prison years for 3 4 7 7 11 12 12 19 22 23 compute the margin of error at 95 confidence level of the year 23396
Uploaded: 2023-08-20T11:56:54-08:00
Duration: 2 min 50 s
Channel: Jerelyn Nevil
Description: we randomly selected ten 10 defendants in a state prison they have been sentenced to prison years for 3 4 7 7 11 12 12 19 22 23 compute the margin of error at 95 confidence level of the year 23396

          We randomly selected ten (10) defendants in a state prison. They
have been sentenced to prison (years) for:
3
4
7
7
11
12
12
19
22
23
Compute the margin of error at 95% confidence level of the
years. (Round off to three decimal places if necessary).

Added by Kevin P.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Jerelyn Nevil

08/20/2023

Step 1

x̄ = (3 + 4 + 7 + 7 + 11 + 12 + 12 + 19 + 22 + 23) / 10 = 120 / 10 = 12 s = √[(Σ(x - x̄)²) / (n - 1)] = √[(9² + 8² + 5² + 5² + 1² + 0² + 0² + 7² + 10² + 11²) / 9] = √[441 / 9] = √49 = 7 Show more…

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We randomly selected ten (10) defendants in a state prison. They have been sentenced to prison (years) for: 3 4 7 7 11 12 12 19 22 23 Compute the margin of error at 95% confidence level of the years. (Round off to three decimal places if necessary).