We randomly selected ten 10 defendants in a state prison...

We randomly selected ten (10) defendants in a state prison. They have been sentenced to prison (years) for: 3 4 7 7 11 12 12 19 22 23 Compute the margin of error at 95% confidence level of the years. (Round off to three decimal places if necessary).

Transcript

00:01 Hello student, we randomly selected the 10 defendants in the state prison.

00:07 Given number of randomly selected samples are 10.

00:13 Then they have been the sent to the prison years for.

00:18 Their observations are given.

00:21 This is the data which is given.

00:23 Compute the margin of error at alpha equal to 0 .95.

00:29 95 % that is 0 .95.

00:31 Then we have to find margin of error which is equal to question mark.

00:36 And we know that margin of error is equal to t alpha by 2 comma n minus 1 into s upon under root of n.

00:46 Here we can calculate t alpha by 2 comma n minus 1 which is equal to value of alpha is already given.

00:58 Make one correction.

00:59 The value of confidence level is given which is a c.

01:02 And we have to find value of alpha first.

01:04 Then 1 minus alpha equals to c which implies alpha is equal to 0 .05.

01:11 Then put here 0 .05 divided by 2.

01:15 N minus 1 is 9.

01:16 Then by using a statistical table we get the value of t alpha by 2 is equal to 2 .262.

01:28 Then now we have to find value of s.

01:31 And we know that s is equal to under root of summation of xi minus x bar bracket square upon n minus 1.

01:42 Then first before that we have to calculate x bar.

01:46 X bar is equal to summation of xi upon n.

01:50 And the value is already known n equal to 10.

01:52 Then summation of xi...

Question

We randomly selected ten (10) defendants in a state prison. They have been sentenced to prison (years) for: 3 4 7 7 11 12 12 19 22 23 Compute the margin of error at 95% confidence level of the years. (Round off to three decimal places if necessary).

Please give Ace some feedback