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Weak Base 26. A 0.0842 M solution of a weak base has a pH of 10.58. What is the identity of the weak base? ?? Ethylamine (CH$_3$CH$_2$NH$_2$) $4.7 \times 10^{-4}$ Hydrazine (N$_2$H$_4$) $1.7 \times 10^{-6}$ Hydroxylamine (NH$_2$OH) $1.1 \times 10^{-8}$ Pyridine (C$_5$H$_5$N) $1.4 \times 10^{-9}$ Aniline (C$_6$H$_5$NH$_2$) $4.2 \times 10^{-10}$ a. aniline b. pyridine c. ethylamine d. hydrazine Xhydroxylamine 27. Given the following, what will be the approximate equilibrium pH of an aqueous solution of ammonium acetate, NH$_4$CH$_3$CO$_2$? NH$_4^+$ $K_a = 5.69 \times 10^{-10}$ CH$_3$CO$_2^-$ $K_b = 5.71 \times 10^{-10}$ X very basic b. very acidic c. nearly neutral equilibrium pH of an aqueous solution of ammonium

          Weak Base
26. A 0.0842 M solution of a weak base has a pH of 10.58. What is the identity of the weak base?
??
Ethylamine (CH$_3$CH$_2$NH$_2$) $4.7 \times 10^{-4}$
Hydrazine (N$_2$H$_4$)
$1.7 \times 10^{-6}$
Hydroxylamine (NH$_2$OH)
$1.1 \times 10^{-8}$
Pyridine (C$_5$H$_5$N)
$1.4 \times 10^{-9}$
Aniline (C$_6$H$_5$NH$_2$)
$4.2 \times 10^{-10}$
a. aniline
b. pyridine
c. ethylamine
d. hydrazine
Xhydroxylamine
27. Given the following, what will be the approximate equilibrium pH of an aqueous solution of ammonium
acetate, NH$_4$CH$_3$CO$_2$?
NH$_4^+$
$K_a = 5.69 \times 10^{-10}$
CH$_3$CO$_2^-$ 
$K_b = 5.71 \times 10^{-10}$
X very basic
b. very acidic
c. nearly neutral
equilibrium pH of an aqueous solution of ammonium
        
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Weak Base
26. A 0.0842 M solution of a weak base has a pH of 10.58. What is the identity of the weak base?
??
Ethylamine (CH3CH2NH2) 4.7 × 10^-4
Hydrazine (N2H4)
1.7 × 10^-6
Hydroxylamine (NH2OH)
1.1 × 10^-8
Pyridine (C5H5N)
1.4 × 10^-9
Aniline (C6H5NH2)
4.2 × 10^-10
a. aniline
b. pyridine
c. ethylamine
d. hydrazine
Xhydroxylamine
27. Given the following, what will be the approximate equilibrium pH of an aqueous solution of ammonium
acetate, NH4CH3CO2?
NH4^+
Ka = 5.69 × 10^-10
CH3CO2^- 
Kb = 5.71 × 10^-10
X very basic
b. very acidic
c. nearly neutral
equilibrium pH of an aqueous solution of ammonium

Added by Jose Ramon B.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Weak Base Kb Ethylamine (C2H5NH2) 4.710^4 Hydrazine (NH2NH2) 1.710^6 Hydroxylamine (NH2OH) 1.110^-8 Pyridine (C5H5N) 1.4 10^9 Aniline (C6H5NH2) 4.2x10^-10 a. aniline b. pyridine c. ethylamine d. hydrazine A hydroxylamine acetate NH4CHCOO NH4+ Ka=5.69x10^-10 CHCOO- Kb=5.71x10^-10 very basic b. very acidic c. nearly neutral H of an aqueous solution of ammonium
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Transcript

-
00:01 Hello students, n2h4 is a weak base which in the solution is in equilibrium with n2h5 positive plus oh negative.
00:10 The concentration given is 0 .231 molar and ph is 10 .70.
00:17 Using the formula poh is equal to 14 minus ph.
00:23 The poh calculated will be equal to 14 minus 10 .7 which is 3 .3.
00:33 As the concentration of oh minus ions will be equal to 10 raised to power minus poh.
00:46 Substituting its value it is 10 raised to power minus 3 .3.
00:52 Solving this the concentration of oh minus comes out to be 5 .0 multiplied by 10 raised to power minus 4 molar...
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