00:01
Hello students in the question a first we are asked to write null and alternative hypothesis.
00:05
So the null hypothesis is that the two samples come from population with the same mean that is mu1 minus mu2 is equal to 0 and alternative hypothesis says states that two samples come from population with the different means.
00:28
So we can also write this as ha mu1 equal to mu2, ho mu1 equal to mu2 and ha mu1 is not equal to mu2.
00:43
Then the test statistic formula is given by x1 bar minus x2 bar divided by s1 square by n1 plus s2 square by n2 and take the square.
00:59
We are given every values just substitute them.
01:05
So this gives t is equal to 2 .35 minus 2 .67 divided by 0 .95 square by 28 plus 0 .69 square by 37 and take the square root of it.
01:28
So this gives us the test statistics t is equal to minus 1 .5068.
01:48
Then we are asked to find the p value.
01:54
So to find p value we need degrees of freedom.
01:56
So the degrees of freedom formula is s1 square by n1 plus s2 square by n2 and take the square of this and divide by s1 square by n1 whole square by n1 minus 1 plus s2 square by n2 whole square by n2.
02:24
Just substitute everything we get the degrees of freedom is equal to 52 .86 that gives 53...