00:01
Okay, what are we thinking here? combustion of ethane gas with oxygen.
00:18
My products will be carbon dioxide and water.
00:29
So i've got a, i'm going to put a six here, two here, a four here, eight, and a seven here.
00:39
Let me check four carbons, four carbons.
00:42
12 hydrogens, 12 hydrogens.
00:44
14, 8 plus 6 is 14.
00:47
Okay, how many grams of water from 6? 0 .07 grams of ethan and 10 .6 grams of oxygen.
01:21
So how many grams of h2o? we're also asked to find grams of excess.
01:41
Also mass of excess.
01:51
Okay, so let's figure out how many grams of water we can make from each of these.
02:06
So i have 12 .01.
02:14
And i get 30 .08 grams per mole of c2h6.
02:31
I have a 2 to 6 mole ratio for c2h6 and h2o.
02:45
And i've got an 18 .02 grams per mole for h2.
02:56
This will equal 6 .07 times 6 times 18 .02 divided by 30 .08 divided by 2.
03:11
And this will be 10 .9 grams of h2...