What are the Brønsted-Lowry bases in this reaction? $NH_3(aq) + H_2O(l) \longrightarrow NH_4^+(aq) + OH^-(aq)$ $NH_4^+$ and $OH^-$ $H_2O$ and $NH_4^+$ $NH_3$ and $H_3O^+$ $NH_3$ and $OH^-$
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In the given reaction, $NH_3(aq) + H_2O(l) \longrightarrow NH_4^+(aq) + OH^-(aq)$, $NH_3$ accepts a proton from $H_2O$ to form $NH_4^+$. Therefore, $NH_3$ acts as a Brønsted-Lowry base. Show more…
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