What are the coefficients for this reaction when it is...

What are the coefficients for this reaction when it is balanced correctly? (Remember when there is no number written in front of a molecule, it is a 1) N2(g) + 3H2(g) + 2O2 --> 2NH4OH(g) 1,2,1,1 1,2,2,1 2,5,1,2 1,3,2,1 none of these What are the coefficients for this reaction when it is balanced correctly? (Remember when there is no number written in front of a molecule, it is a 1) Al(s) + 3H2CO3(aq) --> Al2(CO3)3(aq) + 3H2(g) 1,2,1,2 1,3,3,1 2,3,1,3 3,2,1,3 1,1,1,1 Complete and balance the following double replacement reaction: Li2CO3(aq) + (NH4)2SO4(aq) --> 2LiNO3(aq) + (NH4)2CO3(s) The products of this reaction before balancing are (NH4)2CO3(s) and LiSO4(aq) NH4CO3(aq) and LiSO4(s) no reaction If the following ions Al3+, Cl-, Sr2+, OH- are placed in a test tube, the precipitate formed is AlCl3 Al(OH)3 SrCl2 Sr(OH)2 no precipitate is formed What type of reaction is the following reaction? Co(s) + H2SO4(aq) --> Co2(SO4)3(aq) + H2(g) combination decomposition single replacement double replacement neutralization Write the net ionic reaction for the following double replacement reaction: CuSO4(aq) + Na2S(aq) → CuS(s) + Na2SO4(aq) this is the net ionic reaction Cu2+(aq) + S2- → CuS(s) If a piece of zinc is placed in a solution of aluminum nitrate the result will be a precipitate of Al(NO3)3 the aluminum will dissolve, zinc metal will form a precipitate of Zn(NO3)2 the zinc will dissolve, aluminum metal will form no reaction Complete and balance the following neutralization reaction: Ca(OH)2(aq) + 2HClO3 --> Ca(ClO3)2(aq) + 2H2O What are the products of this reaction before balancing? CaClO3 and H2O Consider the following reaction Ca(s) + 2HCl(aq) --> CaCl2(aq) + H2(g) How many moles of CaCl2 can be produced from 4 moles of HCl? 2 moles Consider the following reaction Ca(s) + 2HCl(aq) --> CaCl2(aq) + H2(g) What is the mass of CaCl2 that can be produced from 0.621 g of HCl? 0.408 g

Transcript

0:00 Hello.

00:01 So in the first question that is given n2 plus h2 plus o2 it gives nh 4oh.

00:11 We need to find out the coefficient for this.

00:13 But for that, let us first balance this equation.

00:17 So the balanced equation will be as we can say here that there is on the right hand side 5 hydrogen are there and on the right hand side only 2 hydrogen are there.

00:28 So we can and also on the left side nitrogen is 2 and nitrogen is 1 on the left and right hand side.

00:39 So therefore on balancing this equation we will have this 2nh 4ohh.

00:48 So here we can see that every element is stable now.

00:52 It is balanced now.

00:53 So now the coefficients are coefficient for the nitrogen it is 1.

01:06 For the hydrogen it is 5, for oxygen it is 1 and for nh 4 -o -h it is 2.

01:19 Now we have the second reaction as al plus h2 co3 which gives al2 co3 plus h2 -s2.

01:33 Now again let us first balance this equation and on balancing this is 2a .l.

01:38 Plus 3h2 co3 it gives al2 co3 co3 plus 3h2.

01:55 Now the coefficients here in this reaction aluminum having 2 coefficient h2 co3 having 3 coefficient which is written before any element.

02:17 Or compound or molecule and al2 co tries contain 1 and for hydrogen it is 3.

02:28 I hope it is clear to you.

02:31 Now in the third part we need to complete the reaction that is l -i -2 -c -o -3 plus n -h -4 twice s -o -4 it is given and we need to complete this reaction.

02:46 So therefore the reaction will be li2 -c -o -3 plus nh4 twice so4.

02:57 It will produce li2s -o -4 plus nh4 twice co3.

03:08 As you can say that this is a double displacement reaction.

03:13 Next we have, see if we put al -1 -3, this aluminum ion, fluoride ion and sr minus 2 strontium ion and hydroxyl ion.

03:27 If we put all these in the test tube, then the precipitate on the form is aloh thrice.

03:38 That is the white color pppt, solid pppt.

03:42 Precipitate is always solid.

03:44 So aluminum hydroxide will form.

03:46 We are given a reaction here that is c -o -cobald plus h -2 -s -o -4 sulfuric acid.

03:55 It will produce co2 -s -o -4 plus h -2.

04:02 So this reaction it is given here and we need to tell what kind of reaction it is.

04:07 So here we can see that this cobalt or this sulfate ion gets displaced from the sulfuric acid and it gets displaced.

04:17 Attached with this co, that is cobalt.

04:21 So therefore we can say that this is the and only one sulphate ion is displaced here.

04:29 No more displacement takes place therefore it is a single displacement or replacement reaction.

04:49 Next question it is asked to tell the net ionic equation.

04:55 So we have a equation here as c -u -s -o -4 plus n -a -2 -s and c -u -s plus n -a -2 -s -4.

05:08 It is given here.

05:10 So the total ionic equation, we know that only aqua's phase undergoes ionization.

05:17 So therefore for this, it will be the total ions will are cu plus 2 plus s -o -4 minus 2 plus here 2na for this one 2na plus s minus 2 and this c o s minus 2 and this c o s it is not the equest therefore it will remain as it is and a 2 s o 4 it will be 2 na positive plus s o 4 minus 2 hence on comparing the left hand side and the right inside we can see that they got cancelled out that is na positive and so 4 negative ion they are spectator ions so they cancelled each other so therefore the net ionic equation is that is c u plus 2 plus s minus 2 it will produce c u s so it will this is the net ionic equation in the next question it is said that when the zinc it is added to the solution of the aluminum nitrate then what will happen so we know that that if we compare the reactivity series between the aluminum and zinc so aluminum it is more reactive than zinc then zinc so if if z -n will be the more reactive than aluminum then it will displace this nitrate iron and get combined with itself.

07:10 But here this aluminum is more reactive.

07:13 Therefore the less reactive cannot displace the more reactive molecule...

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