What are the magnitude and direction of the acceleration of a proton at a point where the electric field has magnitude $33 \mathrm{kN} / \mathrm{C}$ and is directed straight up?
Added by Alex M.
Step 1
First, we need to know the charge of a proton. The charge of a proton is $1.6 \times 10^{-19} \mathrm{C}$. Show more…
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