What are the magnitude and direction of the electric field...

Transcript

00:01 In this question we have to calculate the magnitude and the direction of the electric field that will balance the weight of electron and weight of the proton so first of all we calculate for electron so we can say that for electron we know that the electric force is given by on charge particle of charge that is q which is placed in electric field of magnitude e is that is f is equal to this is e into q and we know that the weight is of electron is that is equals to m g now we have given that this is our equation first and this is equation to as this weight balances this force so we can say that m g is is equal to e into q this is given in the equation now from here we can calculate the value of electric field so we can say that e is equal to this is mg upon q now we have the value here the mass of the electron is this is 9 .1 into 10 to the power minus 31 kilograms we have the value of g that is gravitational acceleration this is 9 .8 meter per second is square and the value of charge q and this is equals to minus of 1 .6 into 10 to the power minus 19 column because electron is negative charge so we can say that after putting all the data in this equation so this is 9 .1 into 10 to the power minus 31 into this is 9 .8 upon minus 1 .6 into 10 to the power minus 19 so we can say this will comes out to be minus 5 .58 into 10 to the power minus 11 newton per column so this is the electric field and as we can say that the weight of the object is acting downward and the electric force so to balance this weight the electric force must be acted upward this is the direction of the electric force but we can say as the direction of electric force on negative charge particle is opposite to the the electric field so we can say that the electric field of the electric field is downward so this is the direction of the electric fold that is downward now similarly we can calculate for proton so we can say that for proton the electric force is given by it is f is equal to this is a into q and this is balanced by the weight of the proton that is mg so from here we can say that the value of e is equal to this is mg by q now for proton we can see that mass of the proton that is m is equals to this is 1 .672 into 10 to the power minus 27 kilograms and the value of charge for proton is 1 .602 into 10 to the power minus 19 cologne so from here we can say that the value of electric field will come out to be this is 1 .67 into 10 to the power minus 27 into 9 .8 upon this is 1 .602 into 10 to the power minus 19s.

04:32 After solving this, we get this is 1 .02 into 10 to the power minus 7 column.

04:40 This is the electric field on proton...

Question

What are the magnitude and direction of the electric field that will balance the weight of (a) an electron and (b) a proton? (Use the data in Table $23.1 .$ )

Question

What are the magnitude and direction of the electric field that will balance the weight of (a) an electron and (b) a proton? (Use the data in Table $23.1 .$ )

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