What are the sign and magnitude of a point charge that produces an electric potential of −2.96 V at a distance of 4.73 mm? C
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99 \times 10^9 \, \text{N m}^2/\text{C}^2 \)), - \( Q \) is the charge, - \( r \) is the distance from the charge. Given: - \( V = -2.96 \, \text{V} \) - \( r = 4.73 \, \text{mm} = 4.73 \times 10^{-3} \, \text{m} \) --- ** Show more…
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