What are the three lowest frequencies for standing waves on a wire 9.88 m long having a mass of 0.107 kg , which is stretched under a tension of 236 N ? \( \quad V=\sqrt{\frac{\pi}{A}} \sqrt{\frac{T}{m}} \)
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\[ \mu = \frac{\text{mass}}{\text{length}} = \frac{0.107 \, \text{kg}}{9.88 \, \text{m}} = 0.01083 \, \text{kg/m} \] Show more…
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