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Hello students, this question consists of three part.
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In the first part, the volume of the gas occupied at 15 degree celsius has been given.
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We have to find out the temperature at which the gas volume is 3 .4 into 10 to the power minus 3 liter.
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At first, we are going to convert this temperature into kelvin by adding 273 and this will be equal to 288 kelvin.
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Now, we are going to apply the charles law that is v1 divided by t1 is equal to v2 divided by t2.
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What we have to find out is the t2 and rearranging this, it will be given as v2 into t1 divided by v1.
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We are going to substitute all the known value.
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The v2 value is 3 .4 into 10 to the power minus 3 into 288 kelvin divided by 1 .70 into 10 to the power minus 3.
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On solving this, we can find out the t2 value.
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The t2 value will be equal to 576 kelvin.
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We are going to convert this into degree celsius, subtracting 273 degree celsius on subtracting this, the t2 value will be equal to 303 degree celsius.
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Coming to the second part of the question, here the v1 and t1 value has been given and the t2 value has been given...