What does "k" in the following equation represent? Group of answer choices equilibrium constant gas constant rate constant rate of the reaction
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The rate of the reaction is first order. Question 4 For some reaction, the equilibrium constant is K = 2.3 x 10^-6. What does this mean? The reactants are in higher concentrations than products at equilibrium. The products are in higher concentrations than reactants at equilibrium. The reactants and products are in equal at equilibrium. The equilibrium value is too small to be measured. Not enough information to answer. Question 5 What is the equilibrium constant expression (K) for the following
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Which of the following are variables (i.e. not constants)? (Select all that apply!) 1) rate constant (k) 2) dB/dt for the reaction A → B 3) reaction velocity (V) 4) ΔG actual 5) standard state equilibrium constant (K eq') 6) ΔG°'
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What is the average value of k (rate constant) for the data set below? Previously, it was determined that the reaction was 1st order in E and 1st order in D. Enter your value of k with 4 digits past the decimal. Rate of reaction Ave. Init. Rate TRIAL [D] M [E] M (kPa/sec) A 0.400 0.400 5.40 x 10^-3 B 0.400 0.200 2.72 x 10^-3 C 0.800 0.400 1.10 x 10^-2
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