Question

What EQUATION is needed to solve this problem: "A gas occupies 12.3 liters at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg?" $PV = nRT$ $P1/T1 = P2 / T2$ $V1/T1 = V2 / T2$ $Patm = PmmHg / 760 mmHg/atm$ $P1 V1 = P2 V2$

          What EQUATION is needed to solve
this problem: "A gas occupies 12.3
liters at a pressure of 40.0 mm Hg.
What is the volume when the pressure
is increased to 60.0 mm Hg?"
$PV = nRT$
$P1/T1 = P2 / T2$
$V1/T1 = V2 / T2$
$Patm = PmmHg / 760 mmHg/atm$
$P1 V1 = P2 V2$

What EQUATION is needed to solve
this problem: "A gas occupies 12.3
liters at a pressure of 40.0 mm Hg.
What is the volume when the pressure
is increased to 60.0 mm Hg?"
PV = nRT
P1/T1 = P2 / T2
V1/T1 = V2 / T2
Patm = PmmHg / 760 mmHg/atm
P1 V1 = P2 V2

Added by Christian M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Amita Prajapat

04/29/2022

Step 1

Step 1: We can use the equation P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume. Show more…

Show all steps

Thanks for your feedback!

What EQUATION is needed to solve this problem: "A gas occupies 12.3 liters at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg? PV=nRT P1/T1=P2/T2 V1/T1=V2/T2 Patm =PmmHg/760 mmHg/atm P1 V1=P2V2