00:02
In this problem, we have a formation of esters in esterification reactions.
00:07
So we know that we have ethanol, and we're going to react it with two different carboxylic acids.
00:21
So first, we react it with propanoic acid.
00:27
So we have three carbons, and i'm actually going to draw it the other right here.
00:40
So it looks like this.
00:41
And we're in the presence of sulfuric acid.
00:47
And then we're also looking at methenoic acid.
00:59
And this also is a reaction done in the presence of sulfuric acid.
01:05
So for esterification reactions, we lose one molecule of water and then form an ester.
01:15
So we'll have something here where we have our carbonyl and oxygen, and then we'll have a carbon group over here.
01:25
And that will be from the alcohol.
01:29
So in this case here, we're going to have these r groups...