00:02
Hi there.
00:04
To predict the hybridization for sulfur in the h .s .o .3 minus ion.
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What we need to do first is to sketch out its list dot structure so that we know the arrangement.
00:21
So to do the lewist dot structure, we need to first determine the number of valence electrons.
00:27
Hydrogens in group one of the periodic table, so it has one.
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Sulfur is in group 6a, so sulfur is going to have six valence electrons, and then there are three oxygens.
00:38
Each oxygen is also in group 6a, so each oxygen also has six valence electrons.
00:45
The charge, the one negative charge, means that this has one additional electron.
00:52
So adding these all together, we get 7, plus 3 times 6 is 18, so that's 25 plus 1, is 26.
01:02
So there are 26 valence electrons.
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Or, in other words, since valence electrons are represented as dots, our completed lewis structure needs to have exactly 26 dots.
01:15
Let's start out and put our sulfur in the center, and it's surrounded by one hydrogen and three oxygen.
01:24
We know we have to have at least a single bond holding these atoms together.
01:29
So let's go ahead and put those in.
01:30
That takes eight of our 26 electrons.
01:33
We have 18 more to put in.
01:36
So let's start completing octets.
01:38
Hydrogen doesn't need anymore because hydrogen only needs two electrons...