What is delta gcircrxn at 298 k for the following reaction...

What is $\Delta G^\circ_{rxn}$ at 298 K for the following reaction? $\Delta G^\circ = \Delta H^\circ - T \Delta S^\circ$ $2Cl_2(g) + SO_2(g) \to SOCl_2(g) + Cl_2O(g)$ Substance $Cl_2(g)$ $SO_2(g)$ $SOCl_2(g)$ $Cl_2O(g)$ $\Delta_f H^\circ$ (kJ mol$^{-1}$) 0 -296.8 -212.5 80.3 $S^\circ$ (J mol$^{-1}$ K$^{-1}$) 223.0 248.1 309.8 266.1 A) 129.3 kJ mol$^{-1}$ B) 133.4 kJ mol$^{-1}$ C) 196.0 kJ mol$^{-1}$ D) 199.8 kJ mol$^{-1}$ E) 229.6 kJ mol$^{-1}$

Transcript

00:01 Hi, so we are asked here to calculate the enthalpy of formation of hcl, one of the products, for this reaction.

00:10 Okay, so to start, we're going to use this equation.

00:15 Entlp.

00:16 Reaction, lota h of reaction is given to the sum of the, some of the enthalpy of formation of the product side, minus the sum of the enthalpy of formation of the reactants.

00:37 Okay.

00:38 We have the delta h of reaction.

00:41 That's equivalent to negative 62 joules.

00:44 So let's write it here.

00:48 Let's just write first.

00:50 The products.

00:52 We have the enthalpy of formation of products.

00:56 We have h2s .4.

01:00 We have here a coefficient of 1 for h2s .4.

01:04 And then for hcl.

01:05 We have two okay let's try to coefficient here one and then we add h cl which has a coefficient of two right here then multiply the enthalpy f formation for h cl which is our unknown here and then we subtract some of the enthalpyf formation the reactive side our reactance s o2 cl2 there's a coefficient of one s -o -2 -c -l -2 plus let me just write it down here.

01:49 What's the coefficient of h -2o? it's 2.

01:54 Then multiply d.

01:56 L -p -a formation of h -2o.

02:00 Okay? so let's plug in the information that we have.

02:04 We have negative 62 kilojoules for the enthalpy of reaction.

02:08 And then, for the given table, formation from the table, for h -2 -s -0 -4, for h -4.

02:15 The enthalpy of formation is negative 814.

02:19 So we have negative 814 plus 2 multiplied by our unknown.

02:27 Entopia formation of h .tl...