Question

What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell (as a working voltaic cell) constructed from half cells with the following half reactions (based on the standard reduction potentials)? Pb2+(aq) + 2e- → Pb(s) E° = -0.126V Fe3+(aq) + e- → Fe2+(s) E° = +0.771 V a. Pb2+(aq) + 2 Fe2+(s) → Pb(s) + 2 Fe3+(aq) Eocell = +0.897 V b. Pb(s) + Fe3+(aq) → Pb2+(aq) + Fe2+(s) Eocell = +0.645 V c. None of the answers is correct. d. Pb2+(aq) + Fe2+(s) → Pb(s) + Fe3+(aq) Eocell = +0.645 V e. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s) Eocell = +0.897 V f. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s) Eocell = +1.416 V

          What is the balanced spontaneous reaction and standard cell potential of an electrochemical cell (as a working voltaic cell) constructed from half cells with the following half reactions (based on the standard reduction potentials)?
Pb2+(aq) + 2e- → Pb(s)            E° = -0.126V 
Fe3+(aq) + e- → Fe2+(s)            E° = +0.771 V 

a. Pb2+(aq) + 2 Fe2+(s) → Pb(s) + 2 Fe3+(aq)        Eocell = +0.897 V 
b. Pb(s) + Fe3+(aq) → Pb2+(aq) + Fe2+(s)              Eocell = +0.645 V 
c. None of the answers is correct. 
d. Pb2+(aq) + Fe2+(s) → Pb(s) + Fe3+(aq)              Eocell = +0.645 V 
e. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s)     Eocell = +0.897 V 
f. Pb(s) + 2 Fe3+(aq) → Pb2+(aq) + 2 Fe2+(s)        Eocell = +1.416 V

Added by Lu-S R.

Question

Please give Ace some feedback