00:01
This question here in the question we are given operating frequency.
00:05
Operating frequency is equals to 9 .5 gigahertz and lengths are given as rho e is equals to 6 .7 centimeter and rho h is equals to 8 .23 centimeter and width wg is given as 22 .53 millimeters and height hg is given as 12 .67 millimeter.
00:35
So let us solve the first part of the question.
00:37
We have to calculate aperture height which is represented by ha and the formula to calculate this is root 3 lambda rho h marking this as equation 1.
00:51
Let us calculate lambda it is c divided by f and c here is 3 multiplied by 10 root 10 and raised to the power 8 divided by f.
01:06
We know it is given in the question and here we will get this as 0 .0316.
01:13
So substituting this in equation number 1.
01:17
So here we will get ha is equals to under root 3 multiplied by 0 .0316 lambda multiplied by 8 .23 multiplied by 10 raised to the power minus 2.
01:40
It is given in centimeters so we have converted that into meters.
01:45
So here we will get ha is equals to 0 .0883 meters.
01:51
Hence we have calculated this.
01:54
Now calculating the aperture width.
01:58
So aperture width formula is wa it will be under root 2 lambda rho e marking this as equation 2.
02:09
Now we will substitute lambda as 0 .0316 and rho e as 6 .7.
02:16
So on substituting these values in the equation 2 we will get wa aperture width as 0 .0651 meters.
02:29
Now coming to the second part of the question the gain of the antenna...