What is the boiling point of a solution of 115.0 g of sucrose, C12H22O11, in 350.0 g of water? (a) Outline the steps necessary to answer the question (b) Answer the question.
Added by Matthew P.
Step 1
Given: Mass of sucrose (solute) = 115.0 g Molar mass of sucrose = 342.3 g/mol Mass of water (solvent) = 350.0 g Molarity (M) = (mass of solute / molar mass of solute) / (mass of solvent in kg) M = (115.0 g / 342.3 g/mol) / (350.0 g / 1000 g/kg) M = (0.3361 mol) / Show more…
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