3. What is the boiling point of a solution of NaCl in water if the solution freezes at -0.93 °C? Kf of water = 1.86 °C/m. Kb of water = 0.512 °C/m. 4. Arrange the following aqueous solutions in order by decreasing freezing points: 0.1 m Na3PO4, 0.1 m C2H5OH, 0.15 m NaCl, and 0.2 m CaCl2. (Hint: No formulas are necessary.)
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We can use the freezing point depression formula: ΔTf = Kf * molality * i where ΔTf is the freezing point depression, Kf is the cryoscopic constant of water (1.86 °C/m), molality is the molality of the solution, and i is the van't Hoff factor (which is 2 for Show more…
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