What is the calculated value of the cell potential at ( 298 mathrm{~K} ) for an electrochemical cell with the following reaction, when the ( mathrm{Hg}^{2+} ) concentration is ( 2.96 imes 10^{-4} mathrm{M} ) and the ( mathrm{Zn}^{2+} ) concentration is ( 1.39 mathrm{M} ) ? [ egin{array}{l} mathrm{Hg}^{2+}(a q)+mathrm{Zn}(s) ightarrow mathrm{Hg}(l)+mathrm{Zn}^{2+}(a q) \ egin{array}{|l|l|} mathrm{Hg}^{2+}(a q)+2 e^{-} ightarrow mathrm{Hg}(l) & E_{mathrm{red}}^{o}=0.855 mathrm{~V} \ hline mathrm{Zn}^{2+}(a q)+2 e^{-} ightarrow mathrm{Zn}(s) & E_{mathrm{red}}^{o}=-0.763 mathrm{~V} \ hline end{array} end{array} ] [ E_{ ext {cell }}= ] The cell reaction as written above is spontaneous for the concentrations given: true false
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Given reduction potentials: Mercury 2+ + 2e- -> Mercury (E° = 0.85 V) Zinc -> Zinc 2+ + 2e- (E° = -0.76 V) Standard cell potential (E°cell) = E°cathode - E°anode E°cell = 0.85 V - (-0.76 V) E°cell = 1.61 V Show more…
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