Composition = 0 wt% C Composition = 0 at% C Temperature = 400 °C Temperature = 752 °F Composition (at% C) 5 10 15 20 25 1600 1538 °C 1493 °C L 1400 2500 ? 1394 °C ? + L 1200 1147 °C ?, Austenite 2.14 4.30 1000 2000 912 °C ? + Fe3C 800 ?+? 1500 727 °C 0.76 600 0.022 ?, Ferrite ? + Fe3C 1085 °C Cementite (Fe3C) 1000 400 0 1 2 3 4 5 6 6.70 (Fe) Composition (wt% C) Temperature (°C) Temperature (°F)
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1. What is the carbon concentration of an iron-carbon alloy for which the fraction of total cementite is 0.10 at 727 °C? 2. Consider 6.0 kg of austenite containing 0.45 wt% C, cooled to below 727 °C: (a) What is the proeutectoid phase? (b) How many kilograms each of total ferrite and cementite form? (c) How many kilograms each of pearlite and the proeutectoid phase form? (d) Sketch and label the resulting microstructure.
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Consider 5 kg of austenite (carbon dissolved in iron) containing 0.65 weight % carbon is slowly cooled just below 727 °C to form ferrite and cementite. Calculate the weight % of ferrite phase (answer as a whole number - no % sign). Assume that the maximum solubility of carbon in iron around that temperature (ferrite phase) be 0.022 weight %, and that the cementite has a fixed composition of 6.67 weight % carbon in iron.
Sri K.
A 0.80 percent C eutectoid plain-carbon steel is slowly cooled from 750°C to a temperature just slightly below 727°C. Assuming the austenite is completely transformed to alpha ferrite and cementite: (Use Iron-Iron carbide phase diagram, Figure 10.28 page 420 in your book) or see fig below: Calculate the approximate weight percent eutectoid cementite formed. a) 5% b) 12% c) 17% d) 21%
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