00:01
Okay, we're getting a bunch of information here and i looked some information up so the we are asked to find the e for the cell at non -standard conditions or at specific concentrations which i will give you later so the first thing i'm gonna do is gonna find my e for my cell and that will be equal to my reduction react minus my oxidation and my reduction is 0 .54 and i'm gonna subtract from that.
00:45
Let me look here my oxidation my reduction minus my oxidation.
01:07
Is this non -spontaneous? okay, so this will be minus 0 .7 996 as written because this one will be switched.
01:48
Okay, and this will be negative 0 .25 9 6 volts okay next since we are well, i guess we're not gonna use that we're gonna use our e for this cell will be equal to the number we just calculated and i'm gonna go up since i was given an f.
02:27
We're gonna subtract from that rt over n f times the ln of q okay, so let me i just want to get my correct values in for my q here.
03:00
I don't want to look at that one okay, let's see if i can get this here.
04:09
Okay, since we're at 298 kelvin and let me go verify.
04:27
We're at 298 kelvin 298 kelvin we can use e for the cell will equal e minus 0 .05 9 2 over n times the log of q okay, and then i'm gonna go figure out what my q's are here...