What is the [CH3COO-]/[CH3COOH] ratio in an acetate buffer (pKa = 4.76) at pH 3? 47:1 1:58 58:1 1:33 1:47
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76, and the pH is 3, we can rearrange the equation to solve for the ratio [A-]/[HA]: 3 = 4.76 + log([A-]/[HA]) -1.76 = log([A-]/[HA]) 10^(-1.76) = [A-]/[HA] 0.022 = [A-]/[HA] Show more…
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