82 \times 10^{-4} \, ^\circ \text{C}^{-1}$, the change in temperature is $40.0^\circ \text{C} - 37.0^\circ \text{C} = 3.0^\circ \text{C}$.
The linear expansion of mercury is given by $\Delta L = L \cdot \alpha \cdot \Delta T$, where $L$ is the original length,
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